A communication satellite is carried from one orbit to another orbit, with radius double that of the first. Its time period in the new orbit will be

24 \sqrt{2} H o u r s

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48 \sqrt{2} H o u r s

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24 H o u r s

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48 H o u r s

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Solution

The correct option is B $48 \sqrt{2} H o u r s$
$T$ for communication satellite $= 24 h r s$
we know that $T α R^{1.5}$ if $R$ is doubled then let new time period be $T_{1}$
So, $\frac{T_{1}}{T} = {(\frac{2 R}{R})}^{1.5} \Rightarrow T_{1} = 2 (2)^{0.5} T = 48 (2)^{0.5} h r s$

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A communication satellite is carried from one orbit to another orbit, with radius double that of the first. Its time period in the new orbit will be

The correct option is B 48√2 HoursT for communication satellite =24 hrswe know that TαR1.5 if R is doubled then let new time period be T1So, T1T=(2RR)1.5⇒T1=2(2)0.5T=48(2)0.5 hrs

The correct option is B $48 \sqrt{2} H o u r s$
$T$ for communication satellite $= 24 h r s$
we know that $T α R^{1.5}$ if $R$ is doubled then let new time period be $T_{1}$
So, $\frac{T_{1}}{T} = {(\frac{2 R}{R})}^{1.5} \Rightarrow T_{1} = 2 (2)^{0.5} T = 48 (2)^{0.5} h r s$