A compact car gets $20$ miles per litre on the highway. Gasoline contains $84.0 %$ carbon by mass and has a density of $0.80 g m l^{- 1}$ . The mass of $C O_{2}$ produced (in $g$ ) during a $50$ mile-trip is:
6160

Open in App

Solution

The correct option is A 6160
Gasoline contains $84.0 % C$ by mass (with density $0.80 g m l^{- 1}$ )
For $20 m i l e s$ $\to$ $1 L$ of gasoline is required
For $50 m i l e s$ $\to$ $x L$ of gasoline is required
⇒ $x = \frac{20}{50}$ = $\frac{2}{5} = 2.5 L$
For $50$ molar we need $2.5 L$ gaseous Gasoline which has $84.0 %$ of carbon by mass
⇒ $84 g$ carbon in $100 g$ gasoline with density = $0.80 g m l^{- 1}$
∴ mass of gasoline
D = $\frac{m a s s}{v o l u m e}$
⇒ $0.80 = \frac{m a s s o f g a s o l i n e}{2.5 \times 103}$
mass of gasoline = $0.80 \times 2.5 \times 103 = 2000 g$
$100 g$ gasoline contains 8 $4 g$ Carbon
$2000 g$ contains $y g$ Carbon
$y = 84 \times \frac{2000}{100} = 1680 g$
$C$ + $O_{2}$ → $C O_{2}$
$12 g C$ $44 g C O_{2}$
1680 gm Carbon will form $x$ g of $C O_{2}$
∴ $x = 16.80 \times \frac{44}{12} = 6160 g$ of $C O_{2}$ is formed

Suggest Corrections

Similar questions

20

84.0 %

0.80 g m l^{- 1}

C O_{2}

g

50

25.0

11.9

12, 000

N = \frac{20 L d}{600 + s^{2}}

\frac{1}{2}

30 miles .

1 qt

5 miles .

Join BYJU'S Learning Program