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Question

A company produces two types of toys : P and Q. Production time of Q is twice that of P and the company has a maximum of 2000 time units per day. The supply of raw material is just sufficient to produce 1500 toys (of any type) per day. Toy type Q requires an electric switch which is available @ 600 pieces per day only. The company makes a profit of Rs. 3 and Rs. 5 on type P and Q respectively.

For maximization of profits, the daily production quantities of P and Q toys should respectively be

A
800, 600
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B
500, 1000
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C
1000, 1000
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D
1000, 500
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Solution

The correct option is D 1000, 500
Given data:

P+2Q2000...(i)

P+Q1500...(ii)

Q600...(iii)

Objective function

zmax=3P+5Q



At point A, z = 3 × 800 + 600 × 5 = 5400

At point B, z = 3 × 1000 + 5 × 500 = 5500

At point C, z = 3 × 1500 + 5 × 0 = 4500

At point D, z = 3 × 0 + 5 × 600 = 3000

Hence z to be maximum at B(1000, 500)

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