A compass needle placed at a distance r from a short magnet in a position shows a deflection of 60o. If the distance is increased to r(3)1/3, then deflection of compass needle, in degrees, is :
A
30
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B
60×31/3
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C
60×32/3
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D
60×3
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Solution
The correct option is D30 tanθ2tanθ1=d31d32=r3[r(3)1/3]3=13 tanθ2=13tanθ1=tan603=√33=1√3