A complex ${[M F_{6}]}^{- x}$ has magnetic moment of 4.91 B.M. whereas ${[M {(C N)}_{6}]}^{- x}$ has zero magnetic moment, metal ion can be :

C o^{+ 2}

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M n^{+ 2}

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F e^{+ 2}

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F e^{+ 3}

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Solution

The correct option is C $F e^{+ 2}$
$\begin{matrix} A c c o r d i n g t o q u e s t i o n . . . . . . . . . . . . f r o m d a t a c a n b e o n c l u d e d t h a t f i r s t c o m p l e z c o m t a i n s 4 u n p a i r e d e l e c t r o n a s i t s m a g n e t i c m o m e n t i s 4.91 B M m a g n e t i c m o m e n t (μ) = \sqrt{n} (n + 2), w h e r e n i s n o . o f u n p a i r e d e l e c t r o n : I n h i g h s p i n c o m p l e x, m e t a l i o n h a s 4 u n p a i r e d e l e c t r o n a n d i n l o w s p i n c o m p l e x i t h a s z e r o u n p a i r e d e l e c t r o n . . . . s o, I o n i s F e^{+ 2}, d^{6} t_{2 g}^{4} e_{g}^{2} i s h i g h s p i n, 4 u n p a i r e d e l e c t r o n . F e^{+ 2}, d^{6} t_{2 g}^{4} e_{g}^{2} l o w s p i n, z e r o u n p a i r e d e l e c t r o n . ∴ i o n i s F e^{+ 2} . s o t h e c o r r e c t p t i o n i s C . \end{matrix}$

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{[{M F}_{6}]}^{- x}

4.91 B . M

{[M {(C N)}_{6}]}^{- x}

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