Question

A complex with the composition $[M{A}_{3}B{]}^{n\pm }$ is found to have no geometrical isomers. The possible structure(s) of the complex is (Where $A$ and $B$ are monodentate ligands).

• A. Tetrahedral
• B. Square planar
• C. Both (a) and (b)
• D. Cannot be predicted

Answer 1

The correct option is C Both (a) and (b)

In both square planar and tetrahedral geometries, only one arrangement is possible. Hence, it cannot have geometrical isomers.

Hence, the correct option is $\text{C}$