A compound 'A' has C, H and O in equal molar ratio with molecular mass of 58. What is the total number of atoms in 'A'?

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Solution

In the compound 'A', the molar ratios of C, H, and O are equal, and the molecular mass is 58.
Molecular formula of (A) $= C_{x} H_{x} O_{x}$ .
The molecular weight of A is $12 x + x + 16 x = 58$ .
$⟹ x = 2$
Hence, the molecular formula of A is $= C_{2} H_{2} O_{2}$ .

It can be $O = C H - C H = O E t h a n e d i a l o r G l y o x a l$ .

The total number of atoms in A is 6.

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A compound 'A' has C, H and O in equal molar ratio with molecular mass of 58. What is the total number of atoms in 'A'?

In the compound 'A', the molar ratios of C, H, and O are equal, and the molecular mass is 58. Molecular formula of (A) =CxHxOx.The molecular weight of A is 12x+x+16x=58.⟹x=2Hence, the molecular formula of A is =C2H2O2.It can be O=CH−CH=OEthanedialorGlyoxal.The total number of atoms in A is 6.