A compound $(A)$ has the molecular formula $C_{2} C l_{3} O H$ . It reduces Fehling's solution and, on oxidation, gives a mono-carboxylic acid. $(A)$ is obtained by the action of chlorine on ethyl alcohol. $(A)$ is:

Methyl chloride

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Monochloro acetic acid

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Chloral

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Chloroform

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Solution

The correct option is C Chloral
The compound reduces Fehling's solution, so it must contain the aldehyde group, $- C H O$ . Again oxidation gives monocarboxylic acid $- C O O H$ , which suggest $A$ contains $- C H O$ group.
$A$ can be prepared from ethyl alcohol by chlorination as follows
$C_{2} H_{5} O H + C l_{2} - H C l - -- \to C H_{3} C H O C H_{3} C H O + 3 C l_{2} - H C l - -- \to C C l_{3} C H O C h l o r a l$

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