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Sodium Thiosulphate

A compound A ...

Question

A compound (A) is greenish crystalline salt which gave the following results :

On heating (A), water vapors and two oxides of sulphur, (C) and (D) are liberated leaving a red-brown residue (E).

What is C, D, and E?

(C) S O_{2} (D) S O_{3} (E) F e_{2} O_{3}

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(C) S O_{3} (D) S O_{2} (E) F e_{2} O_{2}

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(C) S O_{2} (D) S O_{3} (E) F e_{2} O_{2}

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None of these

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Solution

The correct option is A $(C) S O_{2} (D) S O_{3} (E) F e_{2} O_{3}$
The compound (A) is hydrated ferric sulphate (green vitriol) $F e S O_{4} \cdot 7 H_{2} O$
On heating, it loses water of crystallisation to form anhydrous (white) ferric sulphate.
$F e S O_{4} \cdot 7 H_{2} O 300^{o} C - -- \to F e S O_{4}$
On further heating, it gives sulphur dioxide (compound C), sulphur trioxide (compound D) and ferric oxide (compound E).
$2 F e S O_{4} Δ - \to S O_{2} ↑ + S O_{3} ↑ + F e_{2} O_{3}$

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Similar questions

Q. A compound (A) is greenish crystalline salt which gave the following results :
On heating (A), water vapours and two oxides of sulfur, (C) and (D) are liberated leaving a red-brown residue (E).

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Q. A compound (A) is greenish crystalline salt which gave the following results :
On heating (A), water vapours and two oxides of sulfur, (C) and (D) are liberated leaving a red-brown residue (E).
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With H

_{2}

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Compound (A) is a greenish crystalline salt which gives the following results when tested :

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F e S O_{4} . 7 H_{2} O

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F e S O_{4}

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F e S O_{4} . N O o r [F e (H_{2} O)_{6} N O] S O_{4}]

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If true enter 1, else enter 0.

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A compound (A) is greenish crystalline salt which gave the following results : On heating (A), water vapors and two oxides of sulphur, (C) and (D) are liberated leaving a red-brown residue (E). What is C, D, and E?

A compound (A) is greenish crystalline salt which gave the following results :

On heating (A), water vapors and two oxides of sulphur, (C) and (D) are liberated leaving a red-brown residue (E).

What is C, D, and E?