A compound A of formula C₃H₆CI₂ on reaction with alkali can give B of formula C₃H₆O or C of formula C₃H₄. B on oxidation gave a compound of the formula C₃H₆O₂. C with dilute H₂SO₄ CONTAINING Hg²⁺ ion gave D of formula C₃H₆O, which with bromine and NaOH gave the sodium salt of C₂H₄O₂. Then A is:

$C H_{3} C H_{2} C H C l_{2}$

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$C H_{3} C C l_{2} C H_{3}$

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$C H_{2} C l C H_{2} C H_{2} C l$

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$C H_{3} C H C l C H_{2} C l$

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Solution

The correct option is A
$C H_{3} C H_{2} C H C l_{2}$

Since, B and D are different thus, B is CH₃CH₂CHO and so A is CH₃CH₂CHCI_2.

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Similar questions

Q. A compound

^{'} A^{'}

formula of

C_{3} H_{6} C l_{2}

on reaction with alkali can give

^{'} B^{'}

of formula

C_{3} H_{6} O

^{'} C^{'}

of formula

C_{3} H_{4} .^{'} B^{'}

on oxidation gave a compound of the formula

C_{3} H_{6} O_{2} .^{'} C^{'}

with dilute

H_{2} S O_{4}

containing

H g^{2 +}

ion gave

^{'} D^{'}

of formula

C_{3} H_{6} O

, which with bromine and alkali gave the sodium salt of

C_{2} H_{4} O_{2}

. Then

^{'} A^{'}

is :

A compound $A$ of formula $C_{3} H_{6} C l_{2}$ on reaction with alkali can give $B$ of formula $C_{3} H_{6} O$ or $C$ of formula $C_{3} H_{4}$ . $B$ on oxidation gave a compound of the formula $C_{3} H_{6} O_{2}$ . $C$ with dilute $H_{2} S O_{4}$ containing $H g^{2 +}$ ion gave $D$ of formula $C_{3} H_{6} O$ , which with bromine and $N a O H$ gave the sodium salt of $C_{2} H_{4} O_{2}$ . Then $A$ is: