Question

(a) Compound $\left(A\right)$ with molecular formula $C_6{H}_{6}O$ gives violet colour with neutral $Fe{Cl}_3$. $\left(A\right)$ reacts with $CH{Cl}_3$ and $NaOH$ gives two isomers $\left(B\right)$ and $\left(C\right)$ with molecular formula $C_7{H}_6{O}_2$. Compound $\left(A\right)$ reacts with ammonia at $473K$ in the presence of $Zn{Cl}_2$ gives compound $\left(D\right)$ with molecular formula $C_6{H}_{7}N$. Compound $\left(D\right)$ undergoes carbylamine test. Identify $\left(A\right),\left(B\right),\left(C\right)$ and $\left(D\right)$ and explain the reactions.
(b) $\left(A\right)$ is reddish brown metal. It belongs to group 11 and period 4 of the periodic table. When heated below $1370K$. $\left(A\right)$ given a black compound $\left(B\right)$. Wnen heated $1370K$ $\left(A\right)$ gives a red compound $\left(C\right)$. With concentrated nitric acid, $\left(A\right)$ liberates ${NO}_2$ gas and gives compound $\left(D\right)$. Identify $\left(A\right),\left(B\right),\left(C\right)$ and $\left(D\right)$. Explain the reactions.

Answer 1

(a) Compound $A$ is phenol
Compound $B$ is orthohydroxy benzaldehyde
Compound $C$ is para hydroxy benzaldehyde
Compound $D$ is aniline.
(b) $A$ is Copper
$B$ is Curpric oxide (black)
$C$ is Cuprous oxide (red)
$S$ is Copper nitrate
Copper belongs to group 11 and period 4 of the periodic table
$\underset{\left(A\right)}{2Cu}+O_2\underset{}{\overset{below1370K}{\to }}\underset{CupricOxide\left(B\right)}{2CuO\left(black\right)}$
$\underset{\left(A\right)}{4Cu}+O_2\underset{}{\overset{Above1370K}{\to }}\underset{CuprousOxide\left(C\right)}{2{Cu}_{2}O\left(red\right)}$
$\underset{\left(A\right)}{Cu}+4H{NO}_3\left(Conc\right)⟶\underset{\left(D\right)Cupricnitrate}{Cu{\left({NO}_3\right)}_2}+2{NO}_2\uparrow +2H_{2}O$