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Question

A compound AB has an NaCl like structure. The radius of A+ and B is 1.14 A and 1.86 A. What is the minimum distance between two A+ ions in angstroms? (Take 2= 1.41)

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Solution

The edge length is given by the expression,
a=2(r++r)
= 2(1.14+1.86)
= 6 A
The minimum distance between two cations is given by a2
Substituting,
62 = 3×2 = 4.23 A

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