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Empirical & Molecular Formula

A compound co...

Question

A compound consists of 47.8% zinc and 52% chlorine by mass. The empirical formula of the compound is ${Z n}_{x} {C l}_{y}$ , where $x$ and $y$ can have the values:

1 and 1

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1 and 2

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2 and 1

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2 and 3

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Solution

The correct option is B 1 and 2
A compound consists of 47.8% zinc and 52% chlorine by mass.
100 g of compound will have 47.8 g zinc and 52 g chlorine by mass.
The atomic masses of zinc and chlorine are 65.4 g/mol and 35.5 g/mol respectively.
The number of moles of zinc $= \frac{47.8 g}{65.4 g / m o l} = 0.73 m o l$ .
The number of moles of chlorine $= \frac{52 g}{35.5 g / m o l} = 1.47 m o l$ .
The mole ratio zinc : chlorine $= 0.73 : 1.47 = 1 : 2$ .
The empirical formula will be $Z n_{x} C l_{y} = Z n_{1} C l_{2}$ .
Hence, x and y can have the values 1 and 2.

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A compound consists of 47.8% zinc and 52% chlorine by mass. The empirical formula of the compound is ZnxCly, where x and y can have the values:

A compound consists of 47.8% zinc and 52% chlorine by mass. The empirical formula of the compound is ${Z n}_{x} {C l}_{y}$ , where $x$ and $y$ can have the values: