A compound formed by elements X and Y crystallizes in a cubic structure where X is the at corners of the cube and Y is at six face centres. What is the formula of the compound?

X Y

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X Y_{2}

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X Y_{3}

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X Y_{4}

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Solution

The correct option is B $X Y_{3}$
Given that a compound is formed by elements X and Y.
Since X atoms are at the corners, number of atoms of X $= \frac{1}{8} \times 8 = 1$
Since Y is at face centres, number of atoms of Y $= \frac{1}{2} \times 6 = 3$
Hence, the formula is $X Y_{3}$ .

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A compound formed by elements X and Y crystallizes in a cubic structure where X is the at corners of the cube and Y is at six face centres. What is the formula of the compound?

The correct option is B XY3Given that a compound is formed by elements X and Y.Since X atoms are at the corners, number of atoms of X =18×8=1Since Y is at face centres, number of atoms of Y =12×6=3Hence, the formula is XY3.

The correct option is B $X Y_{3}$
Given that a compound is formed by elements X and Y.
Since X atoms are at the corners, number of atoms of X $= \frac{1}{8} \times 8 = 1$
Since Y is at face centres, number of atoms of Y $= \frac{1}{2} \times 6 = 3$
Hence, the formula is $X Y_{3}$ .