Question

A compound forms hexagonal close packed structure. What is the number of octaheral voids in 0.5 mole of it?

Answer 1

Number of atoms in close packaging = 0.5 mol
1 mol has 6.022 ×${10}^{23}$ particles
So,
Number of close−packed particles
= 0.5 × 6.022 × 1$0^{23}$ = 3.011 × 1$0^{23}$ atoms
Now,
Number of octahedral voids = number of atoms in close packaging
So,
Number of octahedral voids = 3.011 × 1$0^{23}$