Question

A compound forms hexagonal close-packed structure. What is the total number of voids in $0.5mol$ of it.How many of these are tetrahedral voids?

Answer 1

Number of atoms in close packaging = $0.5mol$

1 has 6.022 ×10 23 particles

So that

Number of close−packed particles

$=0.5\times 6.022\times {10}^{23}=3.011\times {10}^{23}$

Number of tetrahedral voids $=2\times numberofatomsinclosepackaging$

Plug the values we get

Number of tetrahedral voids $=2\times 3.011\times {10}^{23}$

$=6.022\times {10}^{23}$