Question

A compound has haemoglobin like structure. It has one Fe. It contains 4.6% of Fe. Determine its molecular mass.

Answer 1

Suppose $100mg$ of compound

amount of $Fe$ in compound $=4.6g$

number of mole of compound $=\frac{100}{molarman}$

$=\frac{100}{m}$

Now

$=\frac{100}{M}=1\times \frac{4.6}{56}$

$M=\frac{100\times 56}{4.6}=1217.4gm$

Minimum Molar man of compound be $1217.4gm$