A compound is having an observed rotation of +10.5. The rotation for the pure enantiomer is calculated as +14.
The % optical purity of the compound is:
A
Cannot be predicted.
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B
75%
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C
33.3%
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D
100%
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Solution
The correct option is B75% Optical purity is defined as the ratio of observed rotation to the rotation of pure enantiomer. %Optical purity=Observed optical rotationOptical rotation of pure enantiomer×100%