A compound is made by mixing cobalt(III) nitrite and potassium nitrite solutions in the ratio of $1 : 3$ . The aqueous solution of the compound showed $4$ particles per molecule whereas molar conductivity reveals the presence of 4 ions. The formula of the compound is:

C o (N O_{2})_{3} . 2 K N O_{2}

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C o (N O_{2})_{3} . 3 K N O_{2}

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K_{3} [C o (N O_{2})_{6}]

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K [C o (N O_{2})_{4}]

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Solution

The correct option is C $K_{3} [C o (N O_{2})_{6}]$
$C o (N O_{2})_{3} + 3 K N O_{2} \to K_{3} [C o (N O_{2})_{6}]$
$K_{3} [C o (N O_{2})_{6}] a q . ⇌ 3 K^{+} + [C o (N O_{2})_{6}]^{3 -} (f o u r i o n s)$

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1 : 3

4

The number of ions formed in aqueous solution by the compound $[C o (N H_{3})_{4} C l_{2}] C l$ is:

F e S O_{4}

(N H_{4})_{2} S O_{4}

1 : 1

F e^{2 +}

C u S O_{4}

1 : 4

C u^{2 +}

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