Question

A compound microscope has a magnification 30. The focal length of eyepiece is 5 cm. Assuming that the final image is formed at least distance of distinct vision (25 cm). Find the magnification produced by objective.

Answer 1

Given,

Magnification,$M=30$

Focal length, $f=5cm$

Final distance, $D=25cm$

In a compound microscope, $M=m_o\times m_e$

Thus,

30 = $m_o(1+\frac{D}{f})$

30 = $m_o(1+\frac{25}{5})$

Thus, $m_o=5$