1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# A compound microscope has an objective lens of 1.0 cm focal length and an eye-piece of 2.5 cm of focal length. When the object is placed at 1.1 cm from the objective, the final image is at the least distance of direct vision. Thus, the magnification produced is

A
10
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
B
11
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
C
100
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
D
110
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

## The correct option is D 110given,uo=1.1 cm,fo=1 cm,fe=2.5 cmby lens formula,1vo=1fo+1uo=1−11.1=111vo=11 cmwe know,magnification of compound microscope=vouo(1+Dfe) (when image at D)m=111.1(1+252.5)=10×(10+1)=110hence Option D is correct answer.

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
Compound Microscope
PHYSICS
Watch in App
Explore more
Join BYJU'S Learning Program