A compound of carbon, hydrogen and nitrogen contains these elements in the ratio of 9:1:3.5. If the molecular mass of the compound is 108 g, then identify its correct molecular formula from the options given below.

C_{6} H_{8} N_{2}

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C_{3} H_{4} N

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C_{2} {HN}_{2}

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C_{2} H_{2} N

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Solution

The correct option is A $C_{6} H_{8} N_{2}$
C:H:N = 9 :1:3.5
Molecular mass = 108 g
Molar ratio of C:H:N
= 9/12 : 1/1 : 3.5/14 = 3:4:1
Empirical formula = $C_{3} H_{4} N$ Empirical formula mass
= 12 x 3 + 4 X 1 + 14= 54 g
n = Molecular mass/Empirical mass
Molecular formula = $C_{6} H_{8} N_{2}$

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In a compound C, H and N are present in the ratio 9:1:3.5 by weight. Molecular mass of the compound is 108. What is the molecular formula of the compound?

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A compound of carbon, hydrogen and nitrogen contains these elements in the ratio of 9:1:3.5. If the molecular mass of the compound is 108 g, then identify its correct molecular formula from the options given below.

The correct option is A C6H8N2C:H:N = 9 :1:3.5 Molecular mass = 108 g Molar ratio of C:H:N = 9/12 : 1/1 : 3.5/14 = 3:4:1 Empirical formula = C3H4N Empirical formula mass = 12 x 3 + 4 X 1 + 14= 54 g n = Molecular mass/Empirical mass Molecular formula = C6H8N2

The correct option is A $C_{6} H_{8} N_{2}$
C:H:N = 9 :1:3.5
Molecular mass = 108 g
Molar ratio of C:H:N
= 9/12 : 1/1 : 3.5/14 = 3:4:1
Empirical formula = $C_{3} H_{4} N$ Empirical formula mass
= 12 x 3 + 4 X 1 + 14= 54 g
n = Molecular mass/Empirical mass
Molecular formula = $C_{6} H_{8} N_{2}$