A compound of molecular formula $C_{8} H_{8} O_{2}$ reacts with acetophenone to form a single cross-aldol product in the presence of a base. The same compound on reaction with conc. $N a O H$ forms benzyl alcohol as one of the products. What is the structure of the compound?

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Solution

(Image 1)
Benzaldehyde with acetophenone undergoes cross-aldol condensation and also undergo self oxidation0reduction reaction in presence of a strong base.
$∵$ The molecular formula is $C_{8} H_{8} O_{2}$ , the structure of the compound is
(Image 2)

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Q. A compound of molecular formula

C_{8} H_{8} O_{2}

reacts with acetophenone to form a single cross-aldol product in the presence of base. The same compound on reaction with conc. NaOH forms benzyl alcohol as one of the products. The structure of the compound is :

Q. An organic compound A of molecular formula

C_{7} H_{8}

reacts with

C l_{2}

and NaOH to give an aromatic alcohol B of molecular formula

C_{7} H_{8} O

which liberates

H_{2}

With metallic sodium. Compound B on reaction with

C H_{3} C O O H

in the presence of conc.

H_{2} S O_{4}

forms compound C of molecular formula

C_{9} H_{10} O_{2}

which has the fragrance of jasmine. Identify A; B. and C.
Explain the reactions.

Q. An organic compound C(molecular formula C2 H4 O2) reacts with sodium metal to form a compound B and evolves a gas which burns with a pop sound.Compound C on treatment with an alcohol A in presence of an acid forms a sweet smelling compound S(molecular formula C4 H8 O2).On addition of sodium hydroxide to C it also gives B and water.S on treatment with Sodium Hydroxide solution gives back B and A.
Identify A,B,C and and write chemical equation for all the four reactions involved.

An organic compound A (molecular formula $C_{2} H_{4} O_{2})$ reacts with Na metal to form a compound B and evolves a gas which burns with a pop sound. Compound A on treatment with an alcohol C in the presence of a little of concentrated sulphuric acid forms a sweet-smelling compound D (molecular formula $C_{2} H_{6} O_{2})$ . Compound D on treatment with NaOH solution gives back B and C. Indentity A, B, C and D.

Q. An organic compound A (molecular formula C₂H₄O₂) reacts with Na metal to form a compound B and evolves a gas which burns with a pop sound. Compound A on treatment with an alcohol C in the presence of a little of concentrated sulphuric acid forms a sweet-smelling compound D (molecular formula C₃H₆O₂). Compound D on treatment with NaOH solution gives back B and C. Identify A, B, C and D.

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A compound of molecular formula C8H8O2 reacts with acetophenone to form a single cross-aldol product in the presence of a base. The same compound on reaction with conc. NaOH forms benzyl alcohol as one of the products. What is the structure of the compound?

(Image 1)Benzaldehyde with acetophenone undergoes cross-aldol condensation and also undergo self oxidation0reduction reaction in presence of a strong base.∵ The molecular formula is C8H8O2, the structure of the compound is (Image 2)

A compound of molecular formula $C_{8} H_{8} O_{2}$ reacts with acetophenone to form a single cross-aldol product in the presence of a base. The same compound on reaction with conc. $N a O H$ forms benzyl alcohol as one of the products. What is the structure of the compound?

(Image 1)
Benzaldehyde with acetophenone undergoes cross-aldol condensation and also undergo self oxidation0reduction reaction in presence of a strong base.
$∵$ The molecular formula is $C_{8} H_{8} O_{2}$ , the structure of the compound is
(Image 2)