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A compound of vanadium possesses a magnetic moment of 1.73 BM. The oxidation state of vanadium in this compounds is :

A

1

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B

2

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C

4

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D

can not be predicted.

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Solution

The correct option is C 4
$1.73 = \sqrt{n (n + 2})$
$n = 1$ , where n is the number of unpaired electrons.
Thus, vanadium in oxidation state +4 has one unpaired electron.

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