A compound P is taken in a flat-bottomed flask as shown in the figure. Dilute hydrochloric acid is added drop by drop. A gas Q is evolved which is then passed in a test tube containing R. A solid precipitate S is formed. R is frequently used in white washing. During white washing, a layer of R is applied on the wall and it reacts with gas Q (present in air) to produce a white shiny layer of S on the wall. P, Q, R and S respectively are:

P = N a_{2} S O_{4} Q = S O_{2} R = C a {(O H)}_{2} S = C a S O_{4}

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P = N a_{2} S O_{3} Q = O_{2} R = C a {(O H)}_{2} S = C a O

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P = N a_{2} C O_{3} Q = O_{2} R = C a {(O H)}_{2} S = C a C O_{3}

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P = N a_{2} C O_{3} Q = C O_{2} R = C a {(O H)}_{2} S = C a C O_{3}

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Solution

The correct option is C $P = N a_{2} C O_{3} Q = C O_{2} R = C a {(O H)}_{2} S = C a C O_{3}$
$R$ , which is mostly used in white washing of walls is $Ca (O H)_{2}$

Calcium hydroxide reacts with carbon dioxide $(Q)$ in air to a White shiny layer on the wall.

$\begin{matrix} C a (O H)_{2} (R) + {C O}_{2} (Q) ⟶ {C a C O}_{3} (S) + H_{2} O \end{matrix}$

Carbon dioxide is released on reaction of $H C l$ with any carbonate.

${N a_{2} C O}_{3} (P) + 2 H C l ⟶ 2 N a C l + {C O}_{2} ↑ + H_{2} O$

Option: $D$

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