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Hydrochloric Acid

A compound ‘P...

Question

A compound ‘P’ on treating with concentrated $H_{2} S O_{4}$ forms ‘R’. The product ‘R’ on heating at 460 K forms a zwitterion compound. Identify P, R respectively.

A

Aniline, anilinium hydrogensulphate

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B

Aniline, sulphanilic acid

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C

Anilinium hydrogensulphate, sulphanilic acid

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D

Sulphanilic acid, anilinium hydrogensulphate

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Solution

The correct option is A Aniline, anilinium hydrogensulphate
Aniline (P) reacts with conc. $H_{2} S O_{4}$ to form anilinium hydrogensulphate (R) which on heating at 453-473K produces sulphanilic acid (zwitter ionic compound).

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