Accordingtoquestion...............let,In3.2molarsolution,Wehaveamountofsolute=3.2molVolumeofsolution=1.0LSincethereoccursnochangeinvolumeondissolvingsolute,Volumeofsolvent=1LMassofsolvent=(1.0L)(0.4gmL−1)=(103mL)(0.4gmL−1)=400g=0.4kgMolalityofthesolution=3.2/0.4a=8molkg−1Sothatthesolutionis8molkg−1.