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Molarity

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Question

A compound $H_{2} X$ with molar weight of 80 g is dissolved in a solvent having density of 0.4 g/mol, Assuming no change in volume upon dissolution, the molality of a 3.2 molar solution is .

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Solution

$\begin{matrix} A c c o r d i n g t o q u e s t i o n . . . . . . . . . . . . . . . l e t, I n 3.2 m o l a r s o l u t i o n, W e h a v e a m o u n t o f s o l u t e = 3.2 m o l V o l u m e o f s o l u t i o n = 1.0 L S i n c e t h e r e o c c u r s n o c h a n g e i n v o l u m e o n d i s s o l v i n g s o l u t e, V o l u m e o f s o l v e n t = 1 L M a s s o f s o l v e n t = (1.0 L) (0.4 g m L^{- 1}) = (10^{3} m L) (0.4 g m L^{- 1}) = 400 g = 0.4 k g M o l a l i t y o f t h e s o l u t i o n = 3.2 / 0.4 a = 8 m o l k g^{- 1} S o t h a t t h e s o l u t i o n i s 8 m o l k g^{- 1} . \end{matrix}$

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