A compound with a composition of $87.5 % N$ and $12.5 % H$ was recently discovered. The empirical formula for this compound is:

N H_{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

N_{2} H_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

N_{2} H_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

N H

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $N H_{2}$
Answer is A.
$N H_{2}$
Assuming $100$ g of compounds N would be $87.5$ g and $12.5$ g H, then amount of $N = \frac{87.5}{14} = 6.25$ and $H = \frac{12.5}{1} = 12.5$ mol.
$∴ N : H = 6.25 : 1.25$

$N : H = 1 : 2 = N H_{2}$ .

Suggest Corrections

Similar questions

A compound contains 87.5% by mass of nitrogen and 12.5% by mass of hydrogen. Determine the empirical formula of this compound.

Q. A compounds composition by mass is 50% S and 50% O. What is the empirical formula of this compound?

An organic compound has following composition c=48%,h=8%,n=28%.find out empirical formulae of compound

A hydride of nitrogen contains 87.5 per cent by mass fo nitrogen. Determine the empirical formula of this compound.

A compound has the following percentage composition by mass: carbon 14.4%,hydrogen 1.2% and chlorine 84.5%. Determine the empirical formula of this compound. [H = 1;C=12;Cl = 35.5]

Join BYJU'S Learning Program

A compound with a composition of 87.5%N and 12.5%H was recently discovered. The empirical formula for this compound is:

The correct option is B NH2Answer is A.NH2Assuming 100g of compounds N would be 87.5g and 12.5g H, then amount of N=87.514=6.25 and H=12.51=12.5 mol.∴N:H=6.25:1.25N:H=1:2=NH2.

A compound with a composition of $87.5 % N$ and $12.5 % H$ was recently discovered. The empirical formula for this compound is:

The correct option is B $N H_{2}$
Answer is A.
$N H_{2}$
Assuming $100$ g of compounds N would be $87.5$ g and $12.5$ g H, then amount of $N = \frac{87.5}{14} = 6.25$ and $H = \frac{12.5}{1} = 12.5$ mol.
$∴ N : H = 6.25 : 1.25$

$N : H = 1 : 2 = N H_{2}$ .