Question

A compound with cubic structure is made of elements A and B. A atoms are at the corners of the cube and B atoms are at the face centers. The simplest formula of compound is:

• A. $A_{5}B$
• B. $A{B}_3$
• C. $AB$
• D. $A{B}_6$

Answer 1

The correct option is B $A{B}_3$

If $FCC$ is made of elements A and B,

Number of atoms in $FCC$ = atoms of A at corner + atoms of B at face

= 8 × 1/8 + 6 × 1/2

= 1 + 3

= 4

∴ The formula of the compound is $A{B}_3$

Option B is correct.