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Molecular Formula

A compound wi...

Question

A compound with molar mass $90 g / m o l$ is known to contain $26.66 %$ carbon, $2.22 %$ hydrogen and $71.12 %$ oxygen. Find the molecular of this compound.

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Solution

Consider 90 gm of compound,

carbon = $90 \times \frac{26.66}{100} = 24 g m = 2 m o l$

Hydrogen = $90 \times \frac{2.22}{100} = 2 g m = 2 m o l$

Oxygen = $90 \times \frac{71.22}{100} = 69 g m = 1 m o l$

$∴$ Molecular formula = $C_{2} H_{2} O_{4}$

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