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Question
A compound with molecular mass 180 is acylated with CH3COCl to get a compound with molecular mass 390. The number of amino groups present per molecule of the former compound is :
A compound with molecular mass 180 is acylated with CH3COCl to get a compound with molecular mass 390. The number of amino groups present per molecule of the former compound is :
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Solution
The correct option is D 5
R−NH2+CH3−CO−Cl→R−NH−CO−CH3+HCl
The product formed here is R−NH−CO−CH3 and the initial compound was R−NH2
MW of NH2 is 16
Each CH3−CO additionally increases the molecular wt. by 58−16 = 42
Total increase in MW =390−180=210
Then, number of NH2 groups =21042=5
Hence, the correct option is A.
R−NH2+CH3−CO−Cl→R−NH−CO−CH3+HCl
The product formed here is R−NH−CO−CH3 and the initial compound was R−NH2
MW of NH2 is 16
Each CH3−CO additionally increases the molecular wt. by 58−16 = 42
Total increase in MW =390−180=210
Then, number of NH2 groups =21042=5
Hence, the correct option is A.
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