A compound with molecular mass 180 is acylated with $C H_{3} C O C l$ to get with a compound molecular mass 390. What is the number of amino groups present per molecule of the former compound?

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Solution

For $1 o n e N H_{2} \to 14 + 2 = 16$ It turns into $N H - C O C H_{3} \to 14 + 1 + 12 + 16 + 12 + 3 = 58$ $\Rightarrow 58 - 16 = 42 u n i t s$

So for every $N H_{2}$ , there will be an increase of 42g after acylation.

$\Rightarrow$ The total increase in mass = $390 - 180$ = 210

$\Rightarrow$ No. of amino groups $\frac{210}{42}$ = 5

$\Rightarrow$ 5 amino groups

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A compound with molecular mass 180 is acylated with CH3COCl to get with a compound molecular mass 390. What is the number of amino groups present per molecule of the former compound?

For 1oneNH2→14+2=16 It turns into NH−COCH3→14+1+12+16+12+3=58 ⇒58−16=42unitsSo for every NH2, there will be an increase of 42g after acylation.⇒ The total increase in mass = 390−180 = 210⇒ No. of amino groups 21042 = 5⇒ 5 amino groups

A compound with molecular mass 180 is acylated with $C H_{3} C O C l$ to get with a compound molecular mass 390. What is the number of amino groups present per molecule of the former compound?