A compound X2O3 contains 31.58% oxygen by weight. The atomic weight of X is:
A
344.66g/mol
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B
52.00g/mol
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C
45.01g/mol
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D
104.0g/mol
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Solution
The correct option is B52.00g/mol Let x g/mol be the atomic weight of X. The atomic weight of O=16 g/mol. The molecular weight of X2O3=2(x)+3(16)=2x+48 g/mol Weight percent of O=3(16)2x+48×100=31.58