A compound X consists of 4.8% carbon and 95.2% bromine by mass.If the vapour density of the compound is 252.What is the molecular formula of the compound?

C₂Br₅

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C₄Br₂

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C₂Br₆

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C₆Br₂

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Solution

The correct option is C
C₂Br₆

$\begin{matrix} E l e m e n t & % c o m p o s i t i o n & A t o m i c W e i g h t & A t o m i c r a t i o & S i m p l e s t A t . r a t i o C & 4.8 % & 12 & \frac{4.8}{12} = 0.4 & \frac{0.4}{0.4} = 1 B r & 95.2 % & 80 & \frac{95.2}{80} = 1.19 & \frac{1.19}{0.4} = 3 \end{matrix}$

Therefore, the empirical formula of the compound is $C B r_{3}$ .

Empirical formula mass = 12 + 80 $\times$ 3 = 252

Molecular mass = 2 $\times$ V.D. = 2 $\times$ 252 = 504

n = $\frac{M o l e c u l a r m a s s}{E m p i r i c a l f o r m u l a m a s s} = \frac{504}{252} = 2$

Molecular formula = $(C B r_{3})_{n}$ = $(C B r_{3})_{2}$ = $C_{2} B r_{6}$ .

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Similar questions

A compound X consists of 4.8% carbon and 95.2% bromine by mass.If the vapour density of the compound is 252, what is the molecular formula of the compound?

A compound X consists fo 4.8 % carbon and 95.2 % bromine by mass:
(i) Determine the empirical formula of this compound working correctly to one decimal place (C = 12; Br = 80).
(ii) If the vapour density of the compound is 252, what is the molecular formula of the compound?

A compound 'X' consists of 4.8% carbon and 95.2% bromine by mass.
(i) Determine the empirical formula of this compound working correct to one decimal place.
(C = 12, Br = 80)
(ii) If the vapour density of the compound is 252, what is the molecular formula of the compound?
(iii) Name the type of chemical reaction by which X can be prepared from ethane.

A compound X consists of 4.8% carbon and 95.2% bromine by mass.

Determine the empirical formula of this compound working correct to one decimal place.

[C= 12; Br = 80]

Q. A carbon compound contains 12.8% carbon, 1% hydrogen, 85.1% bromine by mass. The molecular weight of the compound is 187.9. Calculate its molecular formula.

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