A compound X consists of 4.8% carbon and 95.2% bromine by mass.If the vapour density of the compound is 252, what is the molecular formula of the compound?

C₂Br₅

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C₄Br₂

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C₂Br₆

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C₆Br₂

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C₂Br

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Solution

The correct option is C
C₂Br₆

Empirical formula mass = 12 + 80 $\times$ 3 = 252

Molecular mass = 2 $\times$ V.D. = 2 $\times$ 252 = 504

n = $\frac{M o l e c u l a r m a s s}{E m p i r i c a l f o r m u l a m a s s} = \frac{504}{252} = 2$

Molecular formula = $(C B r_{3})_{n}$ = $(C B r_{3})_{2}$ = $C_{2} B r_{6}$ .

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A compound X consists of 4.8% carbon and 95.2% bromine by mass.If the vapour density of the compound is 252.What is the molecular formula of the compound?

A compound X consists fo 4.8 % carbon and 95.2 % bromine by mass:
(i) Determine the empirical formula of this compound working correctly to one decimal place (C = 12; Br = 80).
(ii) If the vapour density of the compound is 252, what is the molecular formula of the compound?

A compound 'X' consists of 4.8% carbon and 95.2% bromine by mass.
(i) Determine the empirical formula of this compound working correct to one decimal place.
(C = 12, Br = 80)
(ii) If the vapour density of the compound is 252, what is the molecular formula of the compound?
(iii) Name the type of chemical reaction by which X can be prepared from ethane.

A compound X consists of 4.8% carbon and 95.2% bromine by mass.

Determine the empirical formula of this compound working correct to one decimal place.

[C= 12; Br = 80]

Q. The empirical formula of a compound is

C H_{2} O

. If the vapour density is 60, what would be the molecular formula of the compound?

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A compound X consists of 4.8% carbon and 95.2% bromine by mass.If the vapour density of the compound is 252, what is the molecular formula of the compound?

The correct option is C C2Br6 Empirical formula mass = 12 + 80 × 3 = 252 Molecular mass = 2 × V.D. = 2 × 252 = 504 n = Molecular massEmpirical formula mass=504252= 2 Molecular formula = (CBr3)n = (CBr3)2 = C2Br6.