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Standard X

Chemistry

Zinc Ion

A compound ...

Question

A compound $(X)$ imparts on a golden yellow flame and shows the following reactions :
$Z n$ powder when boiled with a concentrated aqueous solution of $(X)$ , $H_{2}$ is evolved, What is $X$ ?

K O H

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N a O H

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M g (O H)_{2}

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C a (O H)_{2}

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Solution

The correct option is B $N a O H$
$Z n$ powder when boiled with a concentrated aqueous solution of $(X)$ dissolves and $H_{2}$ is evolved. $Z n + 2 H_{2} O + 2 N a O H \to N a_{2} [Z n (O H)_{4}] + H_{2}$ .
So, $X$ is $N a O H$ .
Hence, option B is correct.

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A compound (X) imparts on a golden yellow flame and shows the following reactions :Zn powder when boiled with a concentrated aqueous solution of (X), H2 is evolved, What is X?

The correct option is B NaOHZn powder when boiled with a concentrated aqueous solution of (X) dissolves and H2 is evolved. Zn+2H2O+2NaOH→Na2[Zn(OH)4]+H2.So, X is NaOH.Hence, option B is correct.

A compound $(X)$ imparts on a golden yellow flame and shows the following reactions :
$Z n$ powder when boiled with a concentrated aqueous solution of $(X)$ , $H_{2}$ is evolved, What is $X$ ?

The correct option is B $N a O H$
$Z n$ powder when boiled with a concentrated aqueous solution of $(X)$ dissolves and $H_{2}$ is evolved. $Z n + 2 H_{2} O + 2 N a O H \to N a_{2} [Z n (O H)_{4}] + H_{2}$ .
So, $X$ is $N a O H$ .
Hence, option B is correct.