MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Halides of Group 16

A compound X,...

Question

$A$ compound $X$ , of boron reacts with $N H_{3}$ on heating to give another compound $Y$ which is called inorganic benzene. The compound $X$ can be prepared by treating $B F_{3}$ with Lithium aluminium hydride. The compounds $X$ and $Y$ are represented by the formulas.

A

B_{3} N_{3} H_{6}, B_{2} H_{6}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

B F_{3}, B_{3} N_{3} H_{6}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

$B_{2} O_{3}, B_{3} N_{3} H_{6}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

B_{2} H_{6}, B_{3} N_{3} H_{6}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $B_{2} H_{6}, B_{3} N_{3} H_{6}$
As per the equation,

$X + N H_{3} \to Y$
(Inorganic benzene)

And

$B F_{3} + L i A l H_{4} \to X$

One needs to find $‘ X^{'} a n d ‘ Y^{'}$

Y is inorganic benzene also known as borazine having formula $B_{3} N_{3} H_{6}$ .

It is called inorganic benzene because it has a similar structure like benzene and it is not organic in nature.

So $Y i s B_{3} N_{3} H_{6}$ .

Borazine / inorganic benzene can be produced by reacting $N H_{3}$ with diborane $B_{2} H_{6}$

$3 B_{2} H_{6} + 6 N H_{3} \to 2 B_{3} N_{3} H_{6} + 12 H_{2}$

$X = B_{2} H_{6}$ $Y = B_{3} N_{3} H_{6}$

Also, to confirm $X = B_{2} H_{6}$ , one can use the second reaction

$4 B F_{3} + 4 L i A l H_{4} \to 2 B_{2} H_{6} + 3 L i F + 3 A l F_{3}$

Thus, it is one of the preparation method of diborane by treating boron trifluoride with $L i A l H_{4}$ in diethyl ether.

Suggest Corrections

thumbs-up

1

Similar questions

X

, of boron reacts with

N H_{3}

on heating to give another compound

Y

which is called inorganic benzene. The compound

X

can be prepared by treating

B F_{3}

with lithium aluminum hydride. The compounds

X

Y

are represented by formula:

Q. A compound of boron X reacts at

200^{\circ} C

temperature with

N H_{3}

to give another compound

Y

which is called as inorganic benzene. The compound

Y

is a colourless liquid and is highly sensitive. Its melting point is

- 57^{\circ} C

X

N H_{3}

and at a still higher temperature gives boron nitride

{(B N)}_{n}

. The compounds

X

Y

respectively are:

Q. A compound of boron X reacts at

200^{\circ} C

temperature with

N H_{3}

to give another compound

Y

which is called as inorganic benzene. The compound

Y

is a colourless liquid and is highly sensitive. Its melting point is

- 57^{\circ} C

X

N H_{3}

and at a still higher temperature gives boron nitride

{(B N)}_{n}

. The compounds

X

Y

respectively are:

Q. Silica reacts with a hydride of superhalogen to form 'X'. On hydrolysis of 'X', another compound 'Y' is formed. 'Y' on heating at

1000^{\circ} C

losses water to form 'Z'.
'Z' can also be prepared by the reaction

(X)

on reduction with

L i A l H_{4}

gives a hydride

(Y)

containing 21.72% hydrogen along with other products. The compound

(Y)

react with air explosively resulting in boron trioxide. Compounds

X

Y

are respectively:

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Halides of Group 16

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Halides of Group 16

Standard XII Chemistry

Join BYJU'S Learning Program

CrossIcon