A compound $X$ with molecular formula $C_{3} H_{8} O$ can be oxidized to a compound $Y$ with the molecular formula $C_{3} H_{6} O_{2}$ . The number of double bonds in $Y$ is:

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Solution

Reaction is: $C H_{3} C H_{2} C H_{2} O H o x i d a t i o n - ---- \to C H_{3} C H_{2} C O O H$
X Y
Y contains one oxygen with a double bond, so the number of double bond is 1.

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A compound X with molecular formula C3H8O can be oxidized to a compound Y with the molecular formula C3H6O2. The number of double bonds in Y is:

Reaction is: CH3CH2CH2OHoxidation−−−−−→CH3CH2COOH X YY contains one oxygen with a double bond, so the number of double bond is 1.

A compound $X$ with molecular formula $C_{3} H_{8} O$ can be oxidized to a compound $Y$ with the molecular formula $C_{3} H_{6} O_{2}$ . The number of double bonds in $Y$ is:

Reaction is: $C H_{3} C H_{2} C H_{2} O H o x i d a t i o n - ---- \to C H_{3} C H_{2} C O O H$
X Y
Y contains one oxygen with a double bond, so the number of double bond is 1.