A compound (X) with molecular formula $C_{3} H_{8} O$ can be oxidized to (Y) with a molecular formula $C_{3} H_{6} O_{2}$ . (X) is most likely to be:

Primary alcohol

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Secondary alcohol

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Aldehyde

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Ketone

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Solution

The correct option is A Primary alcohol
By molecular formula, it can be concluded that,
X is an alcohol and terminal alcohols can undergo
oxidation.Y contains one oxygen with a double bond,
so the number of double bond is 1.

On Oxidation , Propanol gives Propanoic Acid :

$CH_3CH_2CH_2OH \rightarrowCH_3CH_2COOH$
So, X is propanol.
Propanol is Primary Alcohol.

Since, Option A is Correct.

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A compound (X) with molecular formula C3H8O can be oxidized to (Y) with a molecular formula C3H6O2. (X) is most likely to be:

A compound (X) with molecular formula $C_{3} H_{8} O$ can be oxidized to (Y) with a molecular formula $C_{3} H_{6} O_{2}$ . (X) is most likely to be: