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Question

A compound XY crystallizes in BCC lattice with unit cell edge length of 480 pm. If the radius of Y is 225 pm, then the radius of X+ is:-

A
127.5 pm
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B
190.68 pm
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C
225 pm
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D
255 pm
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Solution

The correct option is B 190.68 pm
We know that the sum of the ionic radii is the nearest neighbour distance d.
In case of a body centred cube, d=32a, where a is the unit cell length.
Calculating, we get d=415.68 pm
Since, X++Y=415.68 pm
Therefore, X+=415.68225.00=190.68 pm

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