You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard X

Chemistry

Esterification

A compounds C...

Question

Question 52
A compounds C (molecular formula $C_{2} H_{4} O_{2}$ ) reacts with $Na$ metal to form a compound R and evolves a gas which burns with a pop sound. Compound C on treatment with an alcohol A in presence of acid forms a sweet smelling compound S (molecular compounds $C_{3} H_{6} O_{2}$ ). On addition of $NaOH$ to C, it also gives R and water. S on treatment with $NaOH$ solution gives back R and A. Identify C, R, A, S and write down the reactions involved.

Open in App

Solution

C- Ethanoic acid
R- Sodium salt of Ethanoic acid and gas evolved is Hydrogen
A- Methanol
S- Ester

(a) $2 C H_{3} C O O H + 2 N a \to 2 C H_{3} C O O N a + H_{2} O$
(b) $C H_{3} C O O H + C H_{3} O H C H 3 C O O C H_{3} + H_{2} O$
(c) $C H_{3} C O O H + N a O H \to C H_{3} C O O N a + H_{2} O$
(d) $C H_{3} C O O C H_{3} + N a O H \to C H_{3} C O O N a + C H_{3} O H$

Suggest Corrections

Similar questions

A

compound

C

(molecular formula,

C_{2} H_{4} O_{2}

) reacts with

N a

metal to form a compound

R

and evolves a gas which burns with a pop sound. Compound

C

on treatment with an alcohol

A

in presence of an acid forms a sweet smelling compound

S

(molecular formula,

C_{3} H_{6} O_{2}

). On addition of

N a O H

C

, it also gives R and water. S on treatment with

N a O H

solution gives back

R

and

A

.
Identify

R

and

A

Q. An organic compound A (molecular formula C₂H₄O₂) reacts with Na metal to form a compound B and evolves a gas which burns with a pop sound. Compound A on treatment with an alcohol C in the presence of a little of concentrated sulphuric acid forms a sweet-smelling compound D (molecular formula C₃H₆O₂). Compound D on treatment with NaOH solution gives back B and C. Identify A, B, C and D.

An organic compound A (molecular formula $C_{2} H_{4} O_{2})$ reacts with Na metal to form a compound B and evolves a gas which burns with a pop sound. Compound A on treatment with an alcohol C in the presence of a little of concentrated sulphuric acid forms a sweet-smelling compound D (molecular formula $C_{2} H_{6} O_{2})$ . Compound D on treatment with NaOH solution gives back B and C. Indentity A, B, C and D.