A compounds composition by mass is 50% S and 50% O. What is the empirical formula of this compound?

S O

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{S O}_{2}

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S_{2} O

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S_{2} O_{2}

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S_{3} O_{4}

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Solution

The correct option is D ${S O}_{2}$
Molar mass of $S - a t o m = 32 g / m o l$
Atomic mass of $O - a t o m = 16 g / m o l$
In $S O_{2}$ , the total mass of sulphur present = 32 g.
The total mass of $O - a t o m s$ present $= 2 \times 16 = 32 g$ .
Hence, the ratio of total mass of S and O-atoms present in $S O_{2} = 32 : 32$ .
Total weight of $S O_{2} = 64$
Hence , the composition of $S O_{2}$ by mass is $50$ % S and 50% O.

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