Question

A concave lens made of water $(\mu =1.33)$ is placed inside a glass slab $(\mu =1.5)$. For an object placed between the focus and twice the focus, the image formed is

• A. Virtual
• B. Real, inverted, and magnified
• C. Virtual, inverted, and magnified
• D. Real, inverted, and diminished

Answer 1

The correct option is B Real, inverted, and magnified

Given,
Refractive index of water, ${\mu }_w=1.33$
Refractive index of glass slab, ${\mu }_g=1.5$

Since the water is placed inside the glass slab, so we can say that
​​​the $\text{RI}$ of surrounding, $({\mu }_g=1.5)$ > $\text{RI}$ of lens (water) $({\mu }_w=1.33)$.

Therefore the concave lens shall behave like a convex lens.
So it will form real, inverted and magnified image of the object for, $\because f<u<2f$.