Given,
focal length, f = -15 cm
Distance of image, v = -10 cm
Distance of object, u =?
We know that,
1/v - 1/u = 1/f
So,
1/-10 - 1/u = 1/-15
So, -1/10 + 1/15 = 1/u
(-3 + 2)/30 = 1/u
-1/30 = 1/u
Therefore u = -30 cm
Thus object is placed 30 cm away from the concave lens.
Negative sign shows that object is at 30cm in front of the lens.