A concave mirror forms an inverted image of an object placed at a distance of 15cm from it. If the image is twice as large as the object, where is it formed

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Solution

Dear Student ,
Here in this case the image is twice as large as the object so let us take that the object size is u .
$s o, - m = \frac{v}{u} [a s t h e i m m a g e i s i n v e r t e d] \Rightarrow - 2 = \frac{v}{15} \Rightarrow v = - 30 c m S o t h e i m a g e i s f o r m e d a t a d i s \tan c e 30 c m f r o m t h e c o n c a v e m i r r o r o n t h e s a m e s i d e o f t h e o b j e c t .$
Regards

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A concave mirror forms an inverted image of an object placed at a distance of 15cm from it. If the image is twice as large as the object, where is it formed

Dear Student , Here in this case the image is twice as large as the object so let us take that the object size is u . so ,- m=vu as the immage is inverted⇒-2=v15⇒v=-30 cmSo the image is formed at a distance 30 cm from the concave mirror on the same side of the object . Regards