Question

A concave mirror is initially positioned as shown in Case $\left(I\right)$. Now, some identical parts from a concave mirror are removed and the rest remains in original position as shown in the case $\text{II}$. The number of images formed in case $\text{II},$ if the centre of curvature of all the parts remains same will be

• A. $5$
• B. $3$
• C. $1$
• D. $2$

Answer 1

The correct option is C $1$

In case $\text{II}$, all the mirrors are arranged such that they are still the part of the initial sphere.
Thus, centre of curvature $\left(C\right)$ does not change in case $\text{II}$ and mirrors will not act as an independent one.
$\therefore$ Number of images formed $=1$

Why this question? This question might be confusing if you look at cut segments of mirror. Trick: Observe the change in centre of curvature of cut segments, if there is no change in centre of curvature then mirror's cut is fruitless.