A concave mirror is used to focus the image of a flower on a nearby well $120 c m$ from the flower. If real a lateral magnification of $16$ is desired , the distance of the flower from the mirror should be

8 c m

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12 c m

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80 c m

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120 c m

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Solution

The correct option is A $8 c m$
Let distance $= u .$ Now $\frac{v}{u} = 16$ and $v = u + 120$
$∴ \frac{120 + u}{u} = 16 \Rightarrow 15 u = 120 \Rightarrow u = 8 c m .$

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A concave mirror is used to focus the image of a flower on a nearby well 120 cm from the flower. If real a lateral magnification of 16 is desired , the distance of the flower from the mirror should be

The correct option is A 8 cmLet distance =u. Now vu=16 and v=u+120∴120+uu=16⇒15u=120⇒u=8 cm.

A concave mirror is used to focus the image of a flower on a nearby well $120 c m$ from the flower. If real a lateral magnification of $16$ is desired , the distance of the flower from the mirror should be

The correct option is A $8 c m$
Let distance $= u .$ Now $\frac{v}{u} = 16$ and $v = u + 120$
$∴ \frac{120 + u}{u} = 16 \Rightarrow 15 u = 120 \Rightarrow u = 8 c m .$