A concave mirror is used to focus the image of a flower on a nearby well 120cm from the flower. If a lateral magnification of 16 is desired, the distance of the flower from the mirror should be

8 cm

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12 cm

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80 cm

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120 cm

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Solution

The correct option is A 8 cm
Last distance $= u$ Now $\frac{v}{u} = 16$ and $v = u + 120$

$∴ \frac{120 + u}{u} = 16 \Rightarrow 15 u = 120 \Rightarrow u = 8 c m .$

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A concave mirror is used to focus the image of a flower on a nearby well 120cm from the flower. If a lateral magnification of 16 is desired, the distance of the flower from the mirror should be

The correct option is A 8 cmLast distance =u Now vu=16 and v=u+120 ∴ 120+uu=16⇒15u=120⇒u=8 cm.

The correct option is A 8 cm
Last distance $= u$ Now $\frac{v}{u} = 16$ and $v = u + 120$

$∴ \frac{120 + u}{u} = 16 \Rightarrow 15 u = 120 \Rightarrow u = 8 c m .$