A concave mirror of focal length 15 cm forms an image having twice the linear dimensions of the object. The position of the object when the image is virtual will be
A
22.5 cm
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B
7.5 cm
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C
30 cm
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D
45 cm
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Solution
The correct option is B 7.5 cm f=-15 cm, m=+2 (Positive because image is virtual) ∵m=−vu⇒v=−2u By using mirror formula 1−15=1(−2u)+1u⇒u=−7.5cm